(2/56)(3/56)(4/56)(5/56)(6/56)(7/56)(8/56)(9/56... -

∏n=2kn56=256⋅356⋅456⋯k56product from n equals 2 to k of n over 56 end-fraction equals 2 over 56 end-fraction center dot 3 over 56 end-fraction center dot 4 over 56 end-fraction ⋯ k over 56 end-fraction

The sequence provided follows the general form of a product of fractions where the numerator increases by in each term while the denominator remains constant at . The expression is written as: (2/56)(3/56)(4/56)(5/56)(6/56)(7/56)(8/56)(9/56...

The following graph illustrates how the cumulative product shrinks as more terms are added. Each subsequent term n56n over 56 end-fraction is less than For legal advice, consult a professional

AI responses may include mistakes. For legal advice, consult a professional. Learn more Using Stirling's approximation or computational tools

56!5655the fraction with numerator 56 exclamation mark and denominator 56 to the 55th power end-fraction 3. Calculate the magnitude is an incredibly large number and 565556 to the 55th power

is even larger, the resulting value is extremely small. Using Stirling's approximation or computational tools, the value is determined to be: